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12x^2-72x=-56
We move all terms to the left:
12x^2-72x-(-56)=0
We add all the numbers together, and all the variables
12x^2-72x+56=0
a = 12; b = -72; c = +56;
Δ = b2-4ac
Δ = -722-4·12·56
Δ = 2496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2496}=\sqrt{64*39}=\sqrt{64}*\sqrt{39}=8\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8\sqrt{39}}{2*12}=\frac{72-8\sqrt{39}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8\sqrt{39}}{2*12}=\frac{72+8\sqrt{39}}{24} $
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